Class 8 Physics Index

Class 8 Physics index given here consists of all the topics discussed in class 8 Physics chapters. The listed index is prepared as per the NCERT textbook and the latest CBSE syllabus. Access free study material by clicking on the respective subtopics.

Why is this important?

Before the start of a new academic year, it is helpful to go through the course guide because of the following reasons:

  • It gives you an idea of the learning materials, core books or reference books (if any) that you need for the new session. Knowing this helps you arrange all the required things in time.
  • A clear outline of the topics and learning areas that you will approach throughout the academic year will be presented to you.

Class 8 Physics opens doors to fascinating topics such as force and pressure, friction, and more. These topics are very important for students who wish to pursue a career in the Physics discipline. Master these concepts and build a strong foundation to improve your expertise on the subject.

Stay tuned with BYJU’S for more such interesting articles. Also, register to “BYJU’S – The Learning App” for loads of interactive, engaging Physics-related videos and an unlimited academic assist.

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High School Physics

Force and Pressure Class 8 Worksheets

Last updated on July 17th, 2023 at 02:55 pm

In this post, Force and Pressure Class 8 Worksheets , you will find a worksheet based on Force and Pressure for class 8 students.

Very Short Answer Type Questions

1) State Newton’s second law of motion.

2 ) The mass of a body is a __________ quantity whereas its weight is a _________ quantity.

3 ) Define momentum.

4 ) The rate of change of momentum of a body is proportional to ______________.

5) Define Newton.

6) When the mass of a body is kept constant, its acceleration is directly proportional to the ____ acting on it.

7) A constant force of 2 N acts on a body for 5 seconds to change its velocity. The change in its momentum is _________.

8) N/m 2 = ______________

9) Force per unit ________ = pressure

10) If the applied force is doubled, keeping the area on which it applies the same, then the pressure becomes ___________.

Short Answer Type Questions

1) What is the force exerted by a bullock in pulling a cart of mass 100 kg and accelerating at a rate of 1.5 m/s 2 ?

2 ) An object of mass 10 kg is moving with an initial velocity of 10 m/s. A constant force acts for 4 s on the object giving it a speed of 2 m s–1 in the opposite direction. Find the acceleration and force.

3) A railway wagon of mass 1000 kg is pulled with a force of 10000 N. What is its acceleration?

4 ) If a force of 50 N is applied on a body and it is still at rest, then find the magnitude of static frictional force.

5 ) Find the magnitude of the force applied to a block of mass 5 kg at rest if it moves 36 m in the first 6 seconds. Neglect the force of friction.

6 ) A car changes its speed from 20 km h−1 to 50 km h−1 of mass 3600 kg in 5 s. Determine the net external force applied to the car.

7 )Two forces having magnitudes 3F and 2F, when acting in the same direction simultaneously on a body, the net force is equal to 25 N. Find the value of F.

8)The area of the bottom of a box is 0.5 m 2 and the weight is 150 N, Calculate the pressure exerted by the box on the table.

9) The area of the tip of a pin is 0.25 mm 2 and its weight is 0.05 N. Calculate the pressure (in Pa) exerted by the pin on a wooden plank.

10) Determine the amount of force when the pressure on a 4 m 2 area is 20 Pascal.

11) In a tug of war; when the two teams are pulling the rope, a stage comes when the rope does not move to either side at all. What can you say about the magnitudes and directions of the forces being applied to the rope by the two teams at this stage?

12) Why do mountaineers usually suffer from nose bleeding at high altitudes?

Fill in the Blanks

Fill in the following blanks with suitable words :

(1) A charged body…………an uncharged body towards it.

(2) A drinking straw works on the existence of ……………….pressure.

(3) A force arises due to…………….between two objects.

(4) The pressure exerted by a liquid ……….with depth.

(5) Force has magnitude as well as ……………

(6) The north pole of a magnet…………the north pole of another magnet.

(7) If the two forces applied to an object are equal and act in opposite directions, the net force acting on the object will be …………….

(8) Atmospheric pressure………….with increasing height.

(9) Force acting on a unit area is called ………………

(10) Force could be a ………….or a ………..

(11) To draw water ‘from a well, we have to apply …………. at the rope.

Long Answer Type Questions

1) Explain why the walls of a dam are thicker near the bottom than at the top.

2 ) Explain why atmospheric pressure decreases as we go higher up above the earth’s surface.

3 ) How does the pressure of a liquid depend on its depth? With the help of a labeled diagram show that the pressure of a liquid (say, water) depends on its depth.

4 ) Explain why school bags are provided with wide straps to carry them.

5 ) Explain, why magnetic force is said to be a non-contact force.

6 ) Explain why frictional force is said to be a contact force.

7) Name the type of forces involved in the following : (a) A horse pulling a cart. (b) A sticker attached to the steel almirah without glue. (c) A coin falling to the ground on slipping from hand. (d) A plastic comb rubbed in dry hair picking up tiny pieces of paper. (e) A moving boat coming to rest when rowing is stopped.

Multiple Choice Questions

1) When we press the bulb of a dropper with its nozzle kept in water air in the dropper is seen to escape in the form of bubbles. Once we release the pressure on the bulb, water gets filled in the dropper. The rise of water in the dropper is due to: A. pressure of water B. gravity of the earth C. shape of the rubber bulb D. atmospheric pressure

2) Which of the following are contact forces? A. Friction B. Gravitational force C. Magnetic force D. Muscular force i. A and B ii. B and C iii. A and D iv. B and D

3 ) A rectangular wooden block has length, breadth, and height of 50 cm, 25 cm, and 10 cm, respectively. This wooden block is kept on the ground in three different ways, turn by turn. Which of the following is the correct statement about the pressure exerted by this block on the ground? A. the maximum pressure is exerted when the length and breadth form the base B. the maximum pressure is exerted when length and height form the base C. the maximum pressure is exerted when breadth and height form the base D. the minimum pressure is exerted when length and height form the base

4) The same force Facts on four different objects having the areas given below, one by one. In which case the pressure exerted will be the maximum? A. 20 m 2 B. 50 m 2 C. 10 m 2 D. 100 m 2

5) A pressure of 10 kPa acts on an area of 0.3 m 2 . The force acting on the area will be : A. 3000 N B. 30 N C. 3 N D. 300 N

6) Which of the following is not an effect of force? A. a force can change the speed of a moving object B. a force can change the direction of a moving object C. a force can change the composition of a moving object D. a force can change the shape and size of an object

7) Which of the following is not a non-contact force? A. electrostatic force B. gravitational force C. frictional force D. magnetic force

Hope this Force and Pressure Class 8 Worksheet will help you to evaluate your preparation and understanding of the topic. You may share this with other students and guardians.

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Free Printable Physical Science Worksheets for 8th Class

Physical Science worksheets for Class 8 students: Discover a world of scientific exploration with our free printable resources, designed to help educators inspire young minds in the fascinating realm of Science.

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Physical Science worksheets for Class 8 are an essential tool for teachers looking to engage their students in the exciting world of science. These worksheets cover a wide range of topics, including chemistry, physics, and earth science, providing a comprehensive and interactive learning experience for students. By incorporating these worksheets into their lesson plans, teachers can ensure that their Class 8 students gain a strong foundation in scientific concepts and develop critical thinking skills. Furthermore, these worksheets can be easily customized to suit individual learning styles and classroom needs, making them an invaluable resource for educators looking to enhance their science curriculum.

In addition to Physical Science worksheets for Class 8, teachers can also take advantage of Quizizz, an innovative online platform that offers a variety of interactive quizzes and learning resources. Quizizz allows educators to create engaging, self-paced quizzes that can be used alongside worksheets to reinforce key concepts and assess student understanding. With its extensive library of quizzes covering various science topics, teachers can easily find content that aligns with their Class 8 curriculum. Moreover, Quizizz offers real-time feedback and analytics, enabling teachers to identify areas where students may need additional support or practice. By incorporating both Physical Science worksheets and Quizizz into their teaching strategies, educators can create a dynamic and effective learning environment that fosters a deep understanding and appreciation for science in their Class 8 students.

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Eighth Grade (Grade 8) Physics Questions

You can create printable tests and worksheets from these Grade 8 Physics questions! Select one or more questions using the checkboxes above each question. Then click the add selected questions to a test button before moving to another page.

  • It has a definite shape and volume.
  • It has a definite shape, but no definite volume.
  • It has no definite shape or volume.
  • It has no definite shape, but a definite volume.
  • from a higher temperature to a lower temperature.
  • from a lower temperature to a higher temperature.
  • from inside to outside.
  • from outside to inside.
  • resists flowing
  • takes the shape of its container
  • forms droplets
  • none of the above
  • constant temperature
  • definite shape
  • crystal structure
  • definite volume
  • control group
  • constant speed
  • push or pull
  • linear quantity
  • cannot be determined
  • wavelength increases
  • speed increases
  • amplitude decreases
  • wavelength decreases
  • Freezing point
  • condensation
  • transpiration
  • precipitation
  • evaporation
  • causes all motion.
  • starts stationary objects moving.
  • stops moving objects.
  • is an interaction between two or more objects.
  • all of the above.
  • solid to a liquid.
  • gas to a liquid.
  • solid to a gas.
  • liquid to a solid.

This question is a part of a group with common instructions. View group »

  • Newton's 1st Law of Motion
  • Newton's 3rd Law of Motion
  • Newton's 2nd Law of Motion
  • Equilibrium
  • difference of the two forces.
  • sum of the two forces.
  • only one of the forces acts on the object.
  • neither force can affect the object.
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Light Worksheet-6

  • What are the uses of kaleidoscope?
  • Define dispersion of light.
  • Give an example of natural dispersion.
  • What is the function of rods and cones in our eye?
  • What is blind spot?
  • What is the function of eyelids.
  • What is the Braille system?
  • What is reflection of light? State the laws of reflection.
  • What are the characteristics of image formed by plane mirror?
  • How will you prove that the angle of incidence is equal to the angle of reflection.
  • Explain the structure and working of human eye.

physics worksheet for class 8

  • What is Braille system? Explain.
  • Designers of wallpapers and fabrics and artists use kaleidoscope to get ideas for new pattern.
  • Spitting of light into its colours is knows as dispersion of light.
  • Rainbow is a natural phenomenon showing dispersion.
  • Cones are sensitive to bright light and colour where as rods are sensitive to dim light.
  • At the junction of the optic nerve and retina, there are no sensory cells, so no vision is possible at the spot. This is called the blind spot.
  • Eyelids prevent any object from entering the eye.
  • Louis Braille developed a system for visually challenged person and published. This is known as Braille system. He developed code for common languages.
  • Reflection is a phenomenon in which a beam of light falls on some surface and returns back in different directions. It may be regular or irregular.

Following are the laws of reflection:

(i) When a ray of light falls on a reflected surface it is reflected in such a way that the angle of incidence is equal to the angle of reflection, i.e. ∠i = ∠r

(ii) The incident ray, the normal and the reflected ray all lie in the same plane.

physics worksheet for class 8

  • Characteristics of image formed by a plane mirror are:

(i) Plane mirror form virtual images.

(ii) Plane mirror form erect images.

(iii) Image is laterally inverted.

(iv) Image formed is of the same size as the object.

(v) The distance of image from the mirror is equal to the distance of object from the mirror.

  • Draw lines showing the position of the plane mirror, the incident ray and the reflected ray on the paper with the help of your friends.

Remove the mirror. Draw a line making an angle of 90° to the line representing the mirror at the point where the incident ray strikes the mirror. This line is known as the normal.

The angle between the normal and incident ray is called the angle of incidence (∠i).

The angle between the normal and the reflected ray is known as the angle of reflection (∠r). Measure the angle of incidence and the angle of reflection.

Repeat the activity several times by changing the angle of incidence.

Every time the angle of incidence is equal to the angle of reflection.

This proves that the angle of incidence is equal to the angle of reflection.

  • The eye has a roughly spherical shape.

The outer coat of the eye is white. It is tough so that it can protect the interior part of the eyes from any mishap or accident.

Its transparent front part is called cornea.

Behind the cornea, a dark muscular structure called iris.

In the iris, there is a small opening called pupil.

The size of the pupil is controlled by the iris.

The iris controls the amount of light entering the eye.

Behind the pupil of the eye is a lens which is thicker in the centre.

The lens focuses light on the retina.

The retina contains several nerve cells.

Sensations felt by the nerve cells are then transmitted to the brain through the optic nerve. There are two kinds of cells cones and rods.

  • Braille is a method of writing for visually impaired person. This system was invented by Louis Braille in 1821 and adopted in 1932. He was also a blind person.

In this method text is written on a thick paper using special symbols representing the letters of alphabet. Groups of dots are used to write letters.

There is Braille code for common languages, Mathematics and Scientific notation. Braille system has 63 dots patterns.

Each pattern represents a letter, a combination of letters, a common word or a grammatical sign.

Dots are arranged in cells of two vertical rows of three dots each.

Codes of music and mathematics are different. Any language can be read through the codes of Braille.

physics worksheet for class 8

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  • CBSE Class 8 Science Sound Worksheets

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CBSE Class 8 Science Sound Worksheets with Answers - Chapter 13 - PDF

CBSE Class 8 Science Sound Worksheets with Answers for Chapter 13 in PDF format to download prepared by expert Science teachers from the latest edition of CBSE(NCERT) books. It can be easily downloaded from the website of Vedantu. All the experts have made the solution in a way that can easily clear all your doubts related to the topic. After going through these solutions, you will be able to solve other questions that are related to the topic. Go through this article to get much more detailed information on this topic.

Why do we need to refer to these worksheets?

The Class 8 Science Sound Worksheets are made with a lot of research on the topic so that all the concepts that are related to it are crystal clear. Some of the other reasons to go through these worksheets along with the solutions are as follows:

It can be considered as an ultimate guide to the concepts. 

Most of the questions that are in the worksheets are made keeping in mind the similar pattern that can appear in your exam. 

A thorough revision of the complete chapter can be easily done solely by solving all the questions of the worksheets.

By going through the solutions, one can easily identify the mistakes and can prevent oneself from repeating them. 

The student will also be able to grasp the concepts related to the questions as the solutions are in a very detailed manner. 

The PDF is accessible and can be used as a guide with step-by-step instructions. 

The language used for the solutions is in a very comprehensible language, thus making it easy for all the students to learn and expand their knowledge. 

How to use the worksheets in the best way?

Follow the steps given below to make the most use of the worksheets of the Sound chapter:

First start by reading the chapter from NCERT, so that you can get your basic concepts cleared. 

After reading the chapter, try to solve the intext and the back questions. This will help you analyse your grasp of the concepts. Make sure that you spend some time while brainstorming with the high-order thinking skills questions. 

Once you have done this part, move to the worksheets. As you have already solved the NCERT questions, most of your doubts related to the topics must have been cleared by now. This will help you solve the worksheets questions more easily and it will be less time taking also. 

Take the help from the CBSE Class 8 Science Sound Worksheets with Answers - Chapter 13, which you downloaded from the Vedantu website a few days back. It will help you identify where exactly you are making errors.

The solutions to the worksheet’s questions will also help you to get an idea of how you should frame your answers to get the most marks. Some of the important things that are necessary for proper formations of the answers along with the points that should be highlighted will also be mentioned. 

By solving the worksheet and then analyzing the solutions properly, you will be prepared in the best way possible for your upcoming Science exam. 

Conclusion 

Science worksheets play a very important role when it comes to preparing for an exam. It will help you know where you stand and how hard you need to work to achieve that target set by you. Vedantu is a platform that will help you take a step further towards your goal by providing free solutions to the questions of worksheets along with other study material. So, if you are dedicated to getting towards your goal, then don’t hesitate and avail of the free CBSE Class 8 Science Sound Worksheets with Answers - Chapter 13. Thank you for reading the article.

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FAQs on CBSE Class 8 Science Sound Worksheets

1. What is Vedantu?

If you are not very familiar with this amazing platform, the thing that you should know about this website is that Vedantu is a platform that provides free CBSE Solutions (NCERT) and other study materials for students. It also provides live interactive sessions that can be utilised for clearing the doubt. All you need to do is register yourself. The complete syllabus for any class and also NEET and JEE can be done through this website. With the resources that you will get through this website and your hard work, you can easily ace any exam. 

2. What benefits can be achieved for Math students through Vedantu?

Mathematics Students who are looking for better solutions, can download Class 8 Maths NCERT Solutions to help you to revise the complete syllabus and score more marks in your examinations. Apart from this, registration can be done for doubts sessions in which all the questions along with their concepts will be cleared very easily.

3. What type of questions are available in the worksheets?

The worksheets will contain a variety of questions so that you are well aware of the pattern of the questions that may be asked in the examination. The guidelines given by CBSE are also taken into consideration, thus making it the best way to clear the concepts and do the final revision before the examination. Register Online for Class 8 Science tuition on Vedantu.com to score more marks in your examination.

4. How can we access the CBSE Class 8 Science Sound worksheets with answers - Chapter 13?

The solution of the Sound chapter is available on the Vedantu website and can be accessed for free. These will help you to get a lot better marks in your next Science exam. On the website, select your class and the subject whose solutions you want to download.

Physical Quantities and Measurement

Class 8 - concise physics selina solutions, objective questions.

Write true or false for each statement:

(a) Equal volumes of two different substances have equal masses.

(b) The density of a piece of brass will change by changing its size or shape.

(c) The density of a liquid decreases with increase in its temperature.

(d) Relative density of water is 1.0.

(e) Relative density of a substance is expressed in g cm -3 .

(f) When a body is immersed in a liquid, the buoyant force experienced by the body is equal to the volume of the liquid displaced by it.

(g) A body experiences the same buoyant force while floating in water or alcohol.

(h) A body experiences the same buoyant force when it floats or sinks in water.

(i) A body floats in a liquid when its weight becomes equal to the weight of the liquid displaced by its submerged part.

(j) A body while floating, sinks deeper in a liquid of low density than in a liquid of high density.

(a) False Correct Statement — Equal volumes of two different substances have different masses.

(b) False Correct Statement — The density of a piece of brass will not change by changing its size or shape.

(e) False Correct Statement — Relative density has no unit.

(f) False Correct Statement — When a body is immersed in a liquid, the buoyant force experienced by the body is equal to the weight of the liquid displaced by the immersed part of the body.

(h) False Correct Statement — The buoyant force experience by the body is different when floating or sinking in water.

Fill in the blanks:

(a) 1 kg is the mass of ............... mL of water at 4°C.

(b) Mass = density x ............... .

(c) The S.I. unit of density is ............... .

(d) Density of water is ............... kg m -3 .

(e) 1 g cm -3 = ............... kg m -3 .

(f) The density of a body which sinks in water is ............... than 1000 kg m -3 .

(g) A body sinks in a liquid A, but floats in a liquid B. The density of liquid A is ............... than the density of liquid B.

(h) A body X sinks in water, but a body Y floats on water. The density of the body X is ............... than the density of body Y.

(i) The buoyant force experienced by a body when floating in salt-water is ............... that when floating in pure water.

(j) The weight of a body floating in a liquid is ............... .

(c) kg m -3

(i) equal to

Match the following:

Question 4a

Select the correct alternative:

The correct relation is:

  • Density = Mass x Volume

Mass = Density x Volume

  • Volume = Density x Mass
  • Density = Mass + Volume

Reason — The density of a substance is its mass per unit volume.

Question 4b

The relative density of alcohol is 0.8. Its density is:

800 kg m -3

  • 800 g cm -3
  • 0.8 kg m -3

Relative density of alcohol = Density of alcohol Density of water 0.8 = Density of alcohol 1000 kg m − 3 Density of alcohol = 0.8 × 1000 = 800 kg m − 3 \text{Relative density of alcohol} = \dfrac{\text{Density of alcohol}}{\text{Density of water}} \\[1em] \text{0.8} = \dfrac{\text{Density of alcohol}}{\text{1000 kg m}^{-3}} \\[1em] \text{Density of alcohol} = 0.8 \times 1000 = {\text{800 kg m}^{-3}} Relative density of alcohol = Density of water Density of alcohol ​ 0.8 = 1000 kg m − 3 Density of alcohol ​ Density of alcohol = 0.8 × 1000 = 800 kg m − 3

Question 4c

A block of wood of density 0.8 g cm -3 has a volume of 60 cm -3 . The mass of block is:

Density = Mass Volume 0.8 = Mass 60 Mass = 0.8 × 60 = 48 g \text{Density} = \dfrac{\text{Mass}}{\text{Volume}} \\[1em] \text{0.8} = \dfrac{\text{Mass}}{\text{60}} \\[1em] \text{Mass} = 0.8 \times 60 = 48 \text{g} Density = Volume Mass ​ 0.8 = 60 Mass ​ Mass = 0.8 × 60 = 48 g

Question 4d

The density of aluminium is 2.7 g cm -3 and that of brass is 8.4 g cm -3 . The correct statement is:

  • Equal masses of aluminium and brass have equal volumes.

The mass of a certain volume of brass is more than the mass of equal volume of aluminium.

  • The volume of a certain mass of brass is more than the volume of equal mass of aluminium.
  • Equal volumes of aluminium and brass have equal masses.

Density = Mass Volume \text{Density} = \dfrac{\text{Mass}}{\text{Volume}} Density = Volume Mass ​

So mass of certain volume of brass will be more than the mass of same volume of aluminium as density of brass is more than density of aluminium.

Question 4e

A density bottle has a marking 25 mL on it. It means that:

  • the mass of density bottle is 25 g.
  • the density bottle will store 25 mL of any liquid in it.
  • the density bottle will store 25 mL of water, but more volume of liquid denser than water.
  • the density bottle will store 25 mL of water, but more volume of a liquid lighter than water.

The density bottle will store 25 mL of any liquid in it.

Reason — A density bottle can store specific volume of any density of liquid. Since this bottle is marked 25 mL so it can store 25 mL of any density liquid in it.

Question 4f

The correct statement is:

  • The buoyant force on a body is equal to the volume of the liquid displaced by it.
  • The buoyant force on a body is equal to the volume of the body.

The buoyant force on a body is equal to the weight of the liquid displaced by it.

  • The buoyant force on a body is always equal to the weight of the body.

Reason — According to Principle of Floatation, the buoyant force is equal to the weight of the liquid displaced by the immersed part of the body.

Question 4g

A piece of wood floats on water. The buoyant force on wood will be:

  • more than the weight of the wood piece.
  • equal to the weight of the wood piece.
  • less than the weight of the wood piece.

equal to the weight of the wood piece

Reason — According to Law of Floatation when a body floats on water the weight of the body is equal to the buoyant force.

Question 4h

The weight of a body is more than the buoyant force experienced by it, due to a liquid. The body will:

  • float with its some part outside the liquid.
  • float just below the surface of liquid.
  • float with whole of its volume above the surface of liquid.

Reason — According to the Principle of Floatation, if the weight of the body is more than the buoyant force acting on the body the body will sink into the liquid.

Short/Long Answer Questions

Define the term density of a substance.

The density of a substance is its mass per unit volume i.e.

Name the S.I. unit of density. How is it related to g cm -3 .

The S.I. unit of density is kg m -3 (kilogram per cubic metre). 1 g cm -3 = 1000 kg m -3 .

The density of brass is 8.4 g cm -3 . What do you mean by this statement?

The statement means one cubic centimeter volume of brass has mass of 8.4 g.

Arrange the following substances in order of their increasing density:

Iron, Cork, Brass, Water, Mercury.

Cork < Water < Iron < Brass < Mercury.

The density of cork is the least and that of mercury is the most.

How does the density of a liquid (or gas) vary with temperature?

When temperature increases, volume of most of the liquid increases, so density decreases. Similarly when temperature decreases volume of liquids decreases so density increases. But exception is water which contracts on heating from 0°C to 4°C and expands on heating above 4°C. Water has maximum density at 4 degree celsius.

A given quantity of a liquid is heated. Which of the following quantity will vary and how?

(a) mass (b) volume (c) density

(a) Mass of the liquid remains unaffected on heating.

(b) Volume of the liquid increases with increase in temperature.

(c) Density of liquid decreases on heating because its volume increases and density is inversely proportional to volume.

Describe an experiment to determine the density of the material of a coin.

The density of the material of a coin is determined by the following experiment:

  • We know density is mass per unit volume. So, first mass of the coin is measured by a common beam balance. Let it be M gram.
  • Volume of the coin is measured by a measuring cylinder as shown in the figure given below.
  • Take a measuring cylinder and fill it partly with water.
  • Note the level of water. Let it be V 1 mL.
  • Tie the coin with a thread and gently lower the coin inside the measuring cylinder. Take care that no water splashes out.
  • Note the level of water again. Let it be V 2 mL.
  • Find the volume of the coin (V) by subtracting V 1 from V 2 . V = V 2 - V 1 Density of coin is calculated by the formula: Density = Mass Volume \text{Density} = \dfrac{\text{Mass}}{\text{Volume}} Density = Volume Mass ​

D = M V  g cm − 3 \text{D} = \dfrac{\text{M}}{\text{V}}{\text{ g cm}^{-3}} D = V M ​  g cm − 3

Describe an experiment to determine the density of a liquid.

The density of a liquid is determined by first finding its mass and then its volume.

  • Take an empty beaker and measure its mass by using a common beam balance. Let the mass be M 1 g.
  • Take some amount of liquid and pour it into the empty beaker. Measure its mass again. Let it be M 2 g.
  • The difference between M 2 and M 1 gives the mass(M) of the liquid. M = M 2 - M 1 .
  • Pour the liquid from beaker into a measuring cylinder. Note the volume of the liquid. Let it be V mL or V g cm -3 .
  • Calculate the density of the liquid using the following formula:

What is a density bottle? How is it used to find the density of a liquid?

A density bottle is a specially designed bottle which is used to determine the density of a liquid. The figure of density bottle is shown below:

Determination of Density of a Liquid using the Density Bottle

  • Measure the mass of empty density bottle using a beam balance. Let it be M 1 g.
  • Remove the stopper of the bottle and fill it with water. Replace the stopper, wipe the outside of bottle dry and measure its mass again. Let it be M 2 g.
  • Empty the bottle and dry it. Fill it with the given liquid, replace the stopper and wipe the outside of bottle dry. Measure its mass. Let it be M 3 g.
  • Calculate the mass of water (M 2 - M 1 ) and the mass of liquid (M 3 - M 1 ).
  • Since density of water is 1 g cm -3 , mass of water contained in bottle is the volume of bottle. Thus,     Mass of liquid = M 3 - M 1     Volume of liquid = M 2 - M 1

∴ Density of liquid = Mass of liquid Volume of liquid = M 3 − M 1 M 2 − M 1  g cm − 3 \therefore \text{Density of liquid} = \dfrac{\text{Mass of liquid}}{\text{Volume of liquid}} \\[1em] = \dfrac{\text{M}_{3}-\text{M}_{1}}{\text{M}_{2}-\text{M}_{1}}{\text{ g cm}^{-3}} ∴ Density of liquid = Volume of liquid Mass of liquid ​ = M 2 ​ − M 1 ​ M 3 ​ − M 1 ​ ​  g cm − 3

Question 10

Define the term relative density of a substance.

The relative density of a substance is defined as the ratio of the density of a substance to the density of water. The symbol used for relative density is R.D. Thus,

R.D. = Density of the substance Density of water \text{R.D.} = \dfrac{\text{Density of the substance}}{\text{Density of water}} R.D. = Density of water Density of the substance ​

Question 11

What is the unit of relative density?

Relative density has no unit because it is the ratio of two densities.

Question 12

Distinguish between density and relative density.

Question 13

Explain the meaning of the statement 'Relative density of aluminium is 2.7'.

Relative density of aluminium is 2.7 means a piece of aluminium of any volume has mass 2.7 times that of an equal volume of water.

Question 14

How does the density of a body and that of a liquid determine whether the body will float or sink into that liquid?

If the density of a body is less than the density of liquid, the body will float on the surface of the liquid. But if the density of a body is more than the density of liquid the body will sink in the liquid.

Question 15

A cork piece floats on water surface while an iron nail sinks in it. Explain the reason.

The density of cork is less than the density of water so it floats on water surface but the density of iron nail is more than the density of water so it sinks in water.

Question 16

Which of the following will sink or float on water? (Density of water = 1 g cm -3 )

  • Body A having density 500 kg m -3
  • Body B having density 2520 kg m -3
  • Body C having density 1100 kg m -3
  • Body D having density 0.85 g cm -3
  • Body A will float on water because its density (500 kg m -3 ) is less than the density of water (1 g cm -3 or 1000 kg m -3 ).
  • Body B will sink in water because its density (2520 kg m -3 ) is more than the density of water (1 g cm -3 or 1000 kg m -3 ).
  • Body C will sink in water because its density (1100 kg m -3 ) is more than the density of water (1 g cm -3 or 1000 kg m -3 ).
  • Body D will float on water because its density (0.85 g cm -3 ) is less than the density of water (1 g cm -3 ).

Question 17

State the law of floatation?

The law of floatation states that — "When a body floats in a liquid, the weight of the liquid displaced by its immersed part is equal to the total weight of the body". i.e., while floating Weight of the floating body = Weight of the liquid displaced by its immersed part (i.e., buoyant force)

Question 18

The density of water is 1.0 g cm -3 . The density of iron is 7.8 g cm -3 . The density of mercury is 13.6 g cm -3 . Answer the following:

(a) Will a piece of iron float or sink in water?

(b) Will a piece of iron float or sink in mercury?

(a) Iron will sink in water as density of iron (7.8 g cm -3 ) is more than the density of water (1 g cm -3 ).

(b) Iron will float in mercury as the density of iron (7.8 g cm -3 ) is less than the density of mercury (13.6 g cm -3 ).

Question 19

The diagram given below shows a body floating in three different liquids A, B and C at different levels.

(a) In which liquid does the body experience the greatest buoyant force?

(b) Which liquid has the least density?

(c) Which liquid has the highest density?

(a) The buoyant force is same in each case as the weight of the body is same in each case and the buoyant force is equal to the weight of the liquid displaced by the immersed part of the body which balances the weight of the body.

(b) Liquid A has the least density as the maximum part of the body is immersed in liquid A.

(c) Liquid C has the highest density as the body immerses the least in liquid C.

Question 20

For a floating body, how is its weight related to the buoyant force?

When a body floats in a liquid, the weight of the liquid displaced by its immersed part (i.e. the buoyant force) is equal to the total weight of the body.

Question 21

Why does a piece of ice float on water?

Density of ice is 0.9 g cm -3 and density of water is 1.0 g cm -3 . Since density of ice is less than density of water, so ice floats on water.

Question 22

Explain why an iron needle sinks in water, but a ship made of iron floats on water.

An iron needle is solid and density of iron is more than that of water. Weight of iron needle is more than the buoyant force of water on it so it sinks in water. Although ship is made of iron but it has hollow space that is filled with air which make its average density less than that of water, so ship floats on water.

Question 23

It is easier to swim in sea water than in river water. Explain the reason.

Sea water contains salts so its density is more than the density of river water. The weight of a person gets balanced by the less immersed part of his body in sea water as compared to that in river water. Thus, it is easier to swim in sea water than in river water.

Question 24

Icebergs floating on sea water are dangerous for ships. Explain the reason.

Density of ice (0.9 g cm -3 ) is less than the density of sea water (1.02 g cm -3 ). So, an iceberg floats in sea water with its large portion submerged inside the water and only a little portion of it is above the surface of water. Thus, a ship can collide with the invisible part of the iceberg under the surface of water. Hence, it is dangerous.

Question 25

Explain why it is easier to lift a stone under water than in air.

When a stone is under water then its weight is less than its weight in air because it experiences an upward buoyant force. Due to apparent loss in weight, it is lighter in water which makes it easier to lift in water than in the air.

Question 26

What is a submarine? How can it be made to dive in water and come to the surface of water?

A submarine is a water tight boat which can travel under water like a ship and it is provided with water tanks.

To make the submarine dive, the tanks are filled with water so that the average density of the submarine becomes greater than the density of sea water, so it sinks into the water.

To make the submarine rise to the surface of water, these tanks are emptied. This makes the average density of the submarine less than the density of sea water, so the submarine rises up to the surface of water.

Question 27

A balloon filled with hydrogen rises in air. Explain the reason.

The density of hydrogen gas is less than the density of air. So the buoyant force experienced by the balloon due to air is greater than the weight of the balloon. Due to this net upward force balloon rises up in air.

The density of air is 1.28 g litre -1 . Express it in:

(a) g cm -3

(b) kg m -3

(a) The density of air is 1.28 g litre -1 .

1 litre = 1000 cm 3

∴ Density of air in g cm -3 = 1.28 1000 \dfrac{\text{1.28}}{\text{1000}} 1000 1.28 ​

Density of air = 0.00128 g cm -3

(b) Density of air in kg m -3 = Density of air in g cm -3 x 1000 = 0.00128 x 1000 = 1.28 kg m -3

∴ Density of air in kg m -3 = 1.28 kg m -3 .

The dimensions of a hall are 10 m x 7 m x 5 m. If the density of air is 1.11 kg m -3 , find the mass of air in the hall.

Density of air = 1.11 kg m -3

Volume of hall = 10 m x 7 m x 5 m = 350 m 3

Density = Mass Volume Mass = Density × Volume = 1.11 × 350 = 388.5  kg \text{Density}= \dfrac{\text{Mass}}{\text{Volume}} \\[1em] \text{Mass} = \text{Density} \times \text{Volume} \\[1em] = 1.11 \times 350 \\[1em] = 388.5 \text{ kg} Density = Volume Mass ​ Mass = Density × Volume = 1.11 × 350 = 388.5  kg

Hence, the mass of air in the hall = 388.5 kg.

The density of aluminium is 2.7 g cm -3 . Express it in kg m -3 .

Density of Aluminium = 2.7 g cm -3 .

Density of aluminium in kg m -3 = 2.7 x 1000 = 2700 kg m -3

Hence, Density of aluminium = 2700 kg m -3 .

The density of alcohol is 600 kg m -3 . Express it in g cm -3 .

Density of alcohol in g cm − 3 = Density of alcohol in kg m − 3 1000 = 600 1000 = 0.6  g cm − 3 \text{Density of alcohol in g cm}^{-3} = \dfrac{\text{Density of alcohol in kg m}^{-3}}{\text{1000}} \\[1em] = \dfrac{600}{1000} = 0.6 \text{ g cm}^{-3} Density of alcohol in g cm − 3 = 1000 Density of alcohol in kg m − 3 ​ = 1000 600 ​ = 0.6  g cm − 3

Hence, Density of Alcohol in g cm -3 = 0.6 g cm -3 .

A piece of zinc of mass 438.6 g has a volume of 86 cm 3 . Calculate the density of zinc.

Mass of zinc = 438.6 g

Volume of zinc = 86 cm 3

Density of zinc = ?

Density of Zinc = Mass of Zinc Volume of Zinc = 438.6 86 = 5.1  g cm − 3 \text{Density of Zinc} = \dfrac{\text{Mass of Zinc}}{\text{Volume of Zinc}} \\[1em] = \dfrac{\text{438.6}}{\text{86}} = 5.1 \text{ g cm}^{-3} Density of Zinc = Volume of Zinc Mass of Zinc ​ = 86 438.6 ​ = 5.1  g cm − 3

So, Density of Zinc = 5.1 g cm -3 .

A piece of wood of mass 150 g has a volume of 200 cm 3 . Find the density of wood in

(a) C.G.S. unit

(b) S.I. unit

Mass of wood = 150 g

Volume of wood = 200 cm 3

Density of wood = ?

(a) C.G.S. unit of density is g cm -3 .

Density of Wood = Mass of Wood Volume of Wood = 150 200 = 0.75  g cm − 3 \text{Density of Wood}= \dfrac{\text{Mass of Wood}}{\text{Volume of Wood}} \\[1em] = \dfrac{\text{150}}{\text{200}} = 0.75 \text{ g cm}^{-3} Density of Wood = Volume of Wood Mass of Wood ​ = 200 150 ​ = 0.75  g cm − 3

Density of wood = 0.75 g cm -3 .

(b) S.I. unit of density is kg m -3 .

Density of Wood in kg m -3 = Density of Wood in g cm -3 x 1000 = 0.75 x 1000 = 750 kg m -3

So, Density of Wood = 750 kg m -3 .

Calculate the volume of wood of mass 6000 kg if the density of wood is 0.8 g cm -3 .

Density of wood = 0.8 g cm -3 or 800 kg m -3

Mass of wood = 6000 kg

Volume of wood = ?

Density of Wood = Mass of Wood Volume of Wood Volume of Wood = Mass of wood Density of wood = 6000 800 = 7.5  m 3 \text{Density of Wood}= \dfrac{\text{Mass of Wood}}{\text{Volume of Wood}} \\[1em] \text{Volume of Wood}= \dfrac{\text{Mass of wood}}{\text{Density of wood}} \\[1em] = \dfrac{\text{6000}}{\text{800}} = 7.5 \text{ m}^3 Density of Wood = Volume of Wood Mass of Wood ​ Volume of Wood = Density of wood Mass of wood ​ = 800 6000 ​ = 7.5  m 3

So, Volume of wood = 7.5 m 3 .

Calculate the density of a solid from the following data:

(a) Mass of solid = 72 g

(b) Initial volume of water in measuring cylinder = 24 mL

(c) Final volume of water when solid is completely immersed in water = 42 mL

Mass of solid = 72 g

Volume of solid = Final volume of water - Initial volume of water

Volume of solid = 42 - 24 = 18 mL

Density of Solid = Mass of Solid Volume of Solid = 72 18 = 4 \text{Density of Solid}= \dfrac{\text{Mass of Solid}}{\text{Volume of Solid}} \\[1em] = \dfrac{\text{72}}{\text{18}} = 4 Density of Solid = Volume of Solid Mass of Solid ​ = 18 72 ​ = 4

So, Density of solid = 4.0 g cm -3 .

The mass of an empty density bottle is 21.8 g, when filled completely with water it is 41.8 g and when filled completely with liquid it is 40.6 g. Find:

(a) the volume of density bottle.

(b) the relative density of liquid.

Mass of empty density bottle (M 1 ) = 21.8 g

Mass of bottle with water (M 2 ) = 41.8 g

Mass of bottle with liquid (M 3 )= 40.6 g

(a) Mass of water in bottle = M 2 - M 1 = 41.8 - 21.8 = 20 g

Density of water is 1 g cm -3 , so volume of density bottle = 20 mL

(b) Mass of liquid in bottle = M 3 - M 1 = 40.6 - 21.8 = 18.8 g

R.D. of liquid = Mass of Liquid Mass of eq. vol. of water = 18.8 20 = 0.94 \text{R.D. of liquid}= \dfrac{\text{Mass of Liquid}}{\text{Mass of eq. vol. of water}} \\[1em] = \dfrac{\text{18.8}}{\text{20}} = 0.94 R.D. of liquid = Mass of eq. vol. of water Mass of Liquid ​ = 20 18.8 ​ = 0.94

Relative density of liquid = 0.94.

From the following observations, calculate the density and relative density of a brine solution.

Mass of empty density bottle = 22 g

Mass of bottle + water = 50 g

Mass of bottle + brine solution = 54 g

Mass of empty density bottle (M 1 ) = 22 g

Mass of bottle + water (M 2 ) = 50 g

Mass of bottle + brine solution (M 3 ) = 54 g

Mass of water in bottle = M 2 - M 1 = 50 - 22 = 28 g

Density of water is 1 g cm -3 , so volume of density bottle = 28 cm 3 .

Mass of brine solution in bottle = M 3 - M 1 = 54 - 22 = 32 g

Density of brine soln. = Mass of brine soln.  Vol. of brine soln. = 32 28 = 1.14  g cm − 3 \text{Density of brine soln.}= \dfrac{\text{Mass of brine soln.}}{\text{ Vol. of brine soln.}} \\[1em] = \dfrac{\text{32}}{\text{28}} = 1.14 \text{ g cm}^{-3} Density of brine soln. =  Vol. of brine soln. Mass of brine soln. ​ = 28 32 ​ = 1.14  g cm − 3

So, density of brine solution = 1.14 g cm -3 .

R.D. of brine soln. = Mass of brine soln. Mass of eq. vol. of water = 32 28 = 1.14 \text{R.D. of brine soln.}= \dfrac{\text{Mass of brine soln.}}{\text{Mass of eq. vol. of water}} \\[1em] = \dfrac{\text{32}}{\text{28}} = 1.14 R.D. of brine soln. = Mass of eq. vol. of water Mass of brine soln. ​ = 28 32 ​ = 1.14

So, Relative density of brine solution is 1.14.

The mass of an empty density bottle is 30 g, it is 75 g when filled completely with water and 65 g when filled completely with a liquid. Find:

(a) Volume of density bottle,

(b) Density of liquid and

(c) Relative density of liquid.

Mass of empty density bottle (M 1 ) = 30 g

Mass of bottle with water (M 2 ) = 75 g

Mass of bottle with liquid (M 3 )= 65 g

(a) Mass of water in bottle = M 2 - M 1 = 75 - 30 = 45 g

Density of water is 1 g cm -3 , so volume of density bottle = 45 mL.

(b) Mass of liquid in bottle = M 3 - M 1 = 65 - 30 = 35 g

Density of liquid = Mass of liquid  Vol. of liquid = 35 45 = 0.77  g cm − 3 \text{Density of liquid}= \dfrac{\text{Mass of liquid}}{\text{ Vol. of liquid}} \\[1em] = \dfrac{\text{35}}{\text{45}} = 0.77 \text{ g cm}^{-3} Density of liquid =  Vol. of liquid Mass of liquid ​ = 45 35 ​ = 0.77  g cm − 3

So, density of liquid = 0.77 g cm -3 .

(c) R.D. of liquid = Mass of liquid Mass of eq. vol. of water = 35 45 = 0.77 \text{R.D. of liquid}= \dfrac{\text{Mass of liquid}}{\text{Mass of eq. vol. of water}} \\[1em] = \dfrac{\text{35}}{\text{45}} = 0.77 R.D. of liquid = Mass of eq. vol. of water Mass of liquid ​ = 45 35 ​ = 0.77

So, Relative density of liquid is 0.77.

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This page consists of ICSE Class 8 Physics Worksheet prepared by Physics Wallah. Find out all worksheet for class 8 . Do follow NCERT Solutions for class 8 Science prepared by Physics Wallah. For additional information related to the subject you can check the Physics Formula section.

Before solving the Worksheet for Class 8 one must read the textbook of your school board exam and try to read the notes given in Physics Wallah Class 8 notes sections. Students can also download free pdf of Class 8 Physics Notes prepared by teachers and solve important problems provided here with solutions on daily basis to get more scores in school exams and tests. Physics Wallah worksheets for Class 8 ICSE can help students practice with tests and quickly revise lessons learned in the classroom with essential resources such as video lessons, short notes, and sample papers.

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Chapter wise ICSE Worksheet for class 8 science Physics

This section covers the following sheet for class 8 physics.

  • Worksheet -1(The Universe
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  1. CBSE Worksheet for Class 8 Science Physics

    This section covers the following sheet for class 8 physics. Worksheet-1 (FORCE) Worksheet-2 (PRESSURE) Worksheet-3 (FRICTION) Worksheet-4 (SOUND WAVE) Worksheet-8 (LIGHT) Worksheet-5 (ELECTRICITY) Worksheet-6 (RAIN, THUNDER AND LIGHTNING) Worksheet-7 (EARTHQUAKES) Worksheet-9 (NIGHT SKY)

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    Class 8 Physics index given here consists of all the topics discussed in class 8 Physics chapters. The listed index is prepared as per the NCERT textbook and the latest CBSE syllabus. Access free study material by clicking on the respective subtopics. Why is this important?

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    You can create printable tests and worksheets from these Grade 8 Physics questions! Select one or more questions using the checkboxes above each question. Then click the add selected questions to a test button before moving to another page. Previous Page 1 of 107 Next Select All Questions Grade 8 Matter What is a gas?

  13. CBSE class 8 physics light worksheets

    It may be regular or irregular. Following are the laws of reflection: (i) When a ray of light falls on a reflected surface it is reflected in such a way that the angle of incidence is equal to the angle of reflection, i.e. ∠i = ∠r. (ii) The incident ray, the normal and the reflected ray all lie in the same plane.

  14. Class 8 Physics 2 worksheet

    Class 8 Physics 2. Loading ad... Clunysalem1 Member for 3 years 8 months Age: 13-15. Level: grade 8. Language: English (en) ID: 578838. 09/12/2020 ... Interactive Worksheets For Students & Teachers of all Languages and Subjects. Worksheets. Worksheets; Make Interactive Worksheets; Browse Worksheets; Wookbooks. Workbooks; Learn.

  15. CBSE Class 8 Science Sound Worksheets with Answers

    Take the help from the CBSE Class 8 Science Sound Worksheets with Answers - Chapter 13, which you downloaded from the Vedantu website a few days back. It will help you identify where exactly you are making errors. The solutions to the worksheet's questions will also help you to get an idea of how you should frame your answers to get the most ...

  16. Physical Quantities and Measurement

    Get solutions of ICSE Class 8 Concise Physics Selina Chapter 2: Physical Quantities and Measurement. Clear your Physics doubts instantly & get more marks in Physics exam easily. Master the concepts with our detailed explanations & solutions.

  17. CBSE class 8 sound Worksheet

    Answer Question 4 Name the following the words: The time taken by any object to complete one oscillation. The distance between two consecutive crests or troughs. The frequency of sound that is above 20,000 Hz. The frequency of sound that is below 20 Hz. The maximum displacement covered by a particle from its mean position.

  18. CBSE Worksheets for Class 8

    In this section, all subjects CBSE Class 8 Worksheets are provided in the PDF Format only for practice purpose. In order to download the CBSE 8th Std Printable Worksheets, parents/students need to click on the respective subject CBSE Worksheet & then make use of it for better practice and good knowledge about the subjects.

  19. Chapter-wise ICSE Worksheet For Class 8 Science Physics

    Physics Wallah worksheets for Class 8 ICSE can help students practice with tests and quickly revise lessons learned in the classroom with essential resources such as video lessons, short notes, and sample papers.