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Magnetism Physics

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Some of the worksheets displayed are Physics work lesson 20 magnetism, Physics 10 01 magnets name magnets, Work intro to magnetism, Magnetic elds and forces, Work physics high school magnetism, Chapter 27 magnetic field and magnetic forces, Magnetism electricity vocabulary list definitions, Year 8 physics magnets.

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1. Physics Worksheet Lesson 20 Magnetism

2. physics 10-01 magnets name: magnets, 3. worksheet intro to magnetism, 4. magnetic elds and forces, 5. worksheet physics high school magnetism, 6. chapter 27 magnetic field and magnetic forces, 7. magnetism & electricity vocabulary list & definitions, 8. year 8 physics magnets.

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13.A: Electromagnetic Induction (Answers)

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Check Your Understanding

13.1. 1.1 T/s

13.2. To the observer shown, the current flows clockwise as the magnet approaches, decreases to zero when the magnet is centered in the plane of the coil, and then flows counterclockwise as the magnet leaves the coil.

13.4. \(\displaystyle ε=Bl^2ω/2\), with O at a higher potential than S

13.5. 1.5 V

13.6. a. yes;

b. Yes; however there is a lack of symmetry between the electric field and coil, making \(\displaystyle ∮\vec{E}⋅d\vec{l}\) a more complicated relationship that can’t be simplified as shown in the example.

13.7. \(\displaystyle 3.4×10^{−3}V/m\)

13.8. \(\displaystyle P_1,P)2,P_4\)

13.9. a. \(\displaystyle 3.1×10^{−6}V;\)

b. \(\displaystyle 2.0×10^{−7}V/m\)

Conceptual Questions

1. The emf depends on the rate of change of the magnetic field.

3. Both have the same induced electric fields; however, the copper ring has a much higher induced emf because it conducts electricity better than the wooden ring.

5. a. no; b. yes

7. As long as the magnetic flux is changing from positive to negative or negative to positive, there could be an induced emf.

9. Position the loop so that the field lines run perpendicular to the area vector or parallel to the surface.

11. a. CW as viewed from the circuit; b. CCW as viewed from the circuit

13. As the loop enters, the induced emf creates a CCW current while as the loop leaves the induced emf creates a CW current. While the loop is fully inside the magnetic field, there is no flux change and therefore no induced current.

15. a. CCW viewed from the magnet;

b. CW viewed from the magnet;

c. CW viewed from the magnet;

d. CCW viewed from the magnet;

e. CW viewed from the magnet;

f. no current

17. Positive charges on the wings would be to the west, or to the left of the pilot while negative charges would be pulled east or to the right of the pilot. Thus, the left hand tips of the wings would be positive and the right hand tips would be negative.

19. The work is greater than the kinetic energy because it takes energy to counteract the induced emf.

21. The conducting sheet is shielded from the changing magnetic fields by creating an induced emf. This induced emf creates an induced magnetic field that opposes any changes in magnetic fields from the field underneath. Therefore, there is no net magnetic field in the region above this sheet. If the field were due to a static magnetic field, no induced emf will be created since you need a changing magnetic flux to induce an emf. Therefore, this static magnetic field will not be shielded.

23. a. zero induced current, zero force; b. clockwise induced current, force is to the left; c. zero induced current, zero force; d. counterclockwise induced current, force is to the left; e. zero induced current, zero force.

25. a. 3.8 V;

27. \(\displaystyle B=1.5t,0≤t<2.0ms,B=3.0mT,2.0ms≤t≤5.0ms,\)

\(\displaystyle B=−3.0t+18mT,5.0ms<t≤6.0ms,\)

\(\displaystyle ε=−\frac{dΦm}{dt}=−\frac{d(BA)}{dt}=−A\frac{dB}{dt},\)

\(\displaystyle ε=−π(0.100m)^2(1.5T/s)\)

\(\displaystyle =−47mV(0≤t<2.0ms),\)

\(\displaystyle ε=π(0.100m)^2(0)=0(2.0ms≤t≤5.0ms),\)

\(\displaystyle ε=−π(0.100m)^2(−3.0T/s)=94mV(5.0ms<t<6.0ms).\)

29. Each answer is 20 times the previously given answers.

31. \(\displaystyle \hat{n}=\hat{k},dΦ_m=Cysin(ωt)dxdy,\)

\(\displaystyle Φ_m=\frac{Cab^2sin(ωt)}{2}\),

\(\displaystyle ε=−\frac{Cab^2ωcos(ωt)}{2}\).

33. a. \(\displaystyle 7.8×10^{−3}V\);

b. CCW from the same view as the magnetic field

35. a. 150 A downward through the resistor;

b. 232 A upward through the resistor;

c. 0.093 A downward through the resistor

37. 0.0015 V

39. \(\displaystyle \varepsilon=-B_{0} l d \omega \cos (\Omega t) \mathrm{ld}+B_{0} \sin (\Omega t) \mathrm{lv}\)

41. \(\displaystyle ε=Blvcosθ\)

43. a. \(\displaystyle 2×10^{−19}T\);

b. 1.25 V/m;

c. 0.3125 V;

45. 0.018 A, CW as seen in the diagram

47. 9.375 V/m

49. Inside, \(\displaystyle B=μ_0nI,∮\vec{E}⋅d\vec{l}=(πr^2)μ_0n\frac{dI}{dt},\) so, \(\displaystyle E=\frac{μ_0nr}{2}⋅\frac{dI}{dt}\) (inside). Outside, \(\displaystyle E(2πr)=πR^2μ_0n\frac{dI}{dt}\), so, \(\displaystyle E=\frac{μ_0nR^2}{2r⋅\frac{dI}{dt}}\) (outside)

51. a. \(\displaystyle E_{inside}=\frac{r}{2}\frac{dB}{dt}, E_{outside}=\frac{r^2}{2R}\frac{dB}{dt}\);

b. \(\displaystyle W=4.19×10^{−23}J\);

d. \(\displaystyle F_{mag}=4×10^{−13}N, F_{elec}=2.7×10^{−22}N\)

53. \(\displaystyle 7.1μA\)

55. Three turns with an area of \(\displaystyle 1 m^2\)

57. a. \(\displaystyle ω=120πrad/s,ε=850sin120πt V\);

b. \(\displaystyle P=720sin^2120πtW;\);

c. \(\displaystyle P=360sin^2120πtW\)

59. a. B is proportional to Q ;

b. If the coin turns easily, the magnetic field is perpendicular. If the coin is at an equilibrium position, it is parallel.

61. a. 1.33 A;

Additional Problems

63. \(\displaystyle 4.8×10^{6}\) A/s

65. \(\displaystyle 2.83×10^{−4}A\), the direction as follows for increasing magnetic field:

67. 0.375 V

69. a. 0.94 V;

c. 3.52 J/s;

71. \(\displaystyle (\frac{dB}{dt})\frac{A}{2πr}\)

73. a. \(\displaystyle R_f+R_a=\frac{120V}{2.0A}=60Ω\), so \(\displaystyle R_f=50Ω\);

b. \(\displaystyle I=\frac{ε_s−ε_i}{R_f+R_a},⇒ε_i=90V\);

c. \(\displaystyle ε_i=60V\)

Challenge Problems

75. N is a maximum number of turns allowed.

79. \(\displaystyle Φ=\frac{μ_0I_0a}{2π}ln(1+\frac{b}{x})\), so \(\displaystyle I=\frac{μ_0I_0abv}{2πRx(x+b)}ε=\frac{μ_0I_0abv}{2πx(x+b)}\)

81. a. \(\displaystyle 1.01×10^{−6}V\);

b. \(\displaystyle 1.37×10^{−7}V\);

83. a. \(\displaystyle v=\frac{mgRsinθ}{B^2l^2cos^2θ}\);

b. \(\displaystyle mgvsinθ\);

c. \(\displaystyle mcΔT\);

d. current would reverse direction but bar would still slide at the same speed

85. a. \(\displaystyle B=μ_0nI,Φ_m=BA=μ_0nIA\),

\(\displaystyle ε=9.9×10^{−4}V\);

b. \(\displaystyle 9.9×10^{−4}V\);

c. \(\displaystyle ∮\vec{E}⋅d\vec{l}=ε,⇒E=1.6×10^{−3}V/m\)

d. \(\displaystyle 9.9×10^{−4}V\);

e. no, because there is no cylindrical symmetry

87. a. \(\displaystyle 1.92×10^6rad/s=1.83×10^7rpm\);

b. This angular velocity is unreasonably high, higher than can be obtained for any mechanical system.

c. The assumption that a voltage as great as 12.0 kV could be obtained is unreasonable.

89. \(\displaystyle \frac{2μ_0πa^2I_0nω}{R}\)

91. \(\displaystyle \frac{mRv_o}{B^2D^2}\)

Contributors and Attributions

Samuel J. Ling (Truman State University), Jeff Sanny (Loyola Marymount University), and Bill Moebs with many contributing authors. This work is licensed by OpenStax University Physics under a  Creative Commons Attribution License (by 4.0) .

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Selina Concise Physics Class 6 ICSE Solutions – Magnetism

ICSE Solutions Selina ICSE Solutions ML Aggarwal Solutions

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Selina Concise ICSE Solutions for Class 6 Physics Chapter 6 Magnetism

• The first natural magnet was discovered in Magnesia, a town in Greece. It was called the lodestone.
• Artificial magnets are made of iron or steel. They are made of different shapes namely the bar magnet, cylinderical magnet, U-shaped magnet, horseshoe magnet, magnetic needle, and compass.
• The materials which are attracted by a magnet are called magnetic materials. Examples: iron, steel, cobalt.
• The materials which are not attracted by a magnet are called non-magnetic materials. Examples: paper, wood, brass, plastic, copper aluminum, etc.
• A magnet has two poles, a north, and a south pole.
• A magnet has the following properties:
• A magnet attracts small pieces of iron.
• A magnet always rests in the north-south direction, if it is free to swing.
• Like poles repel each other and unlike poles attract each other.
• Poles always exist in pairs, cannot be isolated.
• Magnets are used to separate iron and steel from their mixture with non-magnetic substances. –
• Magnets are used in many electrical appliances such as an electric bells, loud-speaker, etc.
• A magnetic compass is used by sailors and navigators to find the north-south direction.
• Magnetic induction is the process in which a piece of iron temporarily behaves like a magnet in the presence of another magnet.
• When a magnet is placed near an iron piece, the iron piece behaves like a magnet. The end of the iron piece near the north pole of the magnet becomes a south pole while the farther end becomes a north pole.
• It is because of magnetic induction that a magnet attracts a piece of iron.
• An iron piece can be made into a magnet by any of the following methods:
• Magnetic induction
• Single touch method
• Double touch method
• Electrical method
• In the single touch method, we need a single magnet, but in the double touch method we need two magnets, hi these methods, the end touched last by the magnet has the polarity opposite to that of the striking pole.
• Powerful magnets are made by the electrical method.
• Electromagnets or temporary magnets are made of soft iron.
• Permanent magnets are made of steel.
• Electromagnets are used in devices like electric bell, magnetic toys, telephone etc.
• Permanent magnets are used in devices like galvanometer, ammeter, voltmeter etc.
• A magnet can be destroyed by rough handling, by dropping it several tunes, by hammering it repeatedly and by heating it.
• The magnetic field around a magnet is the space in which a magnetic substance such as small iron piece experiences a force of attraction.
• The earth itself behaves like a magnet. It has its own magnetic field.
• The south polarity of the earth is near the geographic north pole and the north polarity of the earth is near the geographic south pole.
• Magnetic keepers are used to store the magnets.
• Magnetic keepers are small pieces of soft iron.

Magnetic objects Iron, Steel, Cobalt, Nickel Non-magnetic objects Wood, Stone Plastic, Rubber Copper, Sand, Gold, Silver, Brass Paper, Aluminium

Test yourself

A. Objective Questions

1. Write true or false for each statement.

(a) Artificial magnets are weaker than the natural magnets. Answer. False Artificial magnets are stronger than the natural magnets.

(b) Poles of a magnet cannot be separated. Answer. True

(c)  A magnet can attract only a magnetic substance. Answer. True

(d)  A magnet has no effect when it is heated to a high temperature. Answer. False. A magnet get demagnetised when it is heated to a very high temperature.

(e) Permanent magnets get easily demagnetised. Answer. False. Permanent magnets cannot be demagnetised.

(f) Magnetic poles occur in pairs. Answer. True

(g) Single touch method is better than the electrical method for making a magnet. Answer. False. Electrical method is better than single touch method.

(h) Magnetic keeper is a wooden piece. Answer. False. Magnetic keepers are the pieces of soft iron.

(i) Copper cannot be magnetised. Answer. True

2. Fill in the blanks

(a) Temporary magnets are usually made up of soft iron. (b) Rough handling destroys the magnetic properties of a magnet. (c) Like poles repel each other. (d) A freely suspended magnet points in the north-south direction. (e) In a magnet, ends have the maximum attractive property. (f) A magnet has two poles.

4. Select the correct answer

(a) If we suspend a magnet freely, it will settle in .

• east-west direction
• north-south direction
• north-east direction
• east-south direction

(b) Making a magnetic substance a magnet by bringing it closer to another magnet without touching it, is

• magnetic induction method
• single touch method
• double touch method
• electrical method

(c) An example of natural magnet is

• none of above

(d) The artificial magnet used to detect direction in the laboratory is

• U-shaped magnet
• horse shoe magnet
• electromagnet
• magnetic compass

B. Short/Long Answer Questions

Question 1. What is a magnet ? Answer: The substances which have the property of attracting iron, are called magnets.

Question 2. What are magnetic and non-magnetic substances ? Give two examples of each. Answer: Magnetic substances: The substances that get attracted by a magnet are called magnetic substances. Iron, steel, cobalt and nickel are magnetic substance Non-magnetic substances : The substances that do not get attracted by a magnet are called non-magnetic substances, e.g., wood, plastic, copper, paper, aluminium, rubber, stone.

Question 3. What are natural and artificial -magnets ? Answer: Natural magnets: Natural magnets are those which are found in nature e.g. load stone. Artificial magnets: Man made magnets are called artificial magnets, e.g. electromagnet.

Question 4. How is an artificial magnet prepared from a natural magnet ? Answer: Pieces of iron or other materials are made magnets by rubbing them with natural magnets (or by passing direct current through a wire wound around them). This is how artificial magnets are made.

Question 5. State two ways of magnetising an iron piece. Answer: The two ways of magnetising an iron piece are:

Question 6. How can magnetic properties of a magnet be destroyed ? Answer:

• By hammering the magnet repeatedly.
• By rough handling
• By heating.

Question 7. Why docs a freely suspended magnet always rest in north- south direction ? Answer: A freely suspended magnet always rest in north-south direction because the north-pole of the magnet lies in the geographic north direction and the south pole of the magnet lies in the geographic south direction. So it aligns itself in N-S direction. As unlike poles attract and like poles repel.

Question 9. Why are the artificial magnets preferred over the natural magnets ? Answer: Artificial magnets are preferred over natural magnets because natural magnets are weak and often irregular in shape, they can readily be magnetised and demagnetised by turning the current on or off in the coil.

Question 10. Describe an experiment to show that the maximum attractive property is at the poles of a magnet. Answer: Take a bar magnet and place a steel pin at some distance. We observe that nothing happens. Now, bring the steel pin near the pole of the bar magnet. We notice that pin sticks to the magnet. This experiment shows that maximum magnetic force acts at the poles of the magnet.

Question 11. State four important properties of a bar magnet. Answer:

• Attractive property: A magnet can attract small pieces of iron filing or other ferromagnetic materials.
• Directive property: If a magnet is suspended horizontally by a thin thread (say silk thread), it rests always pointing north- south direction of earth.
• Like poles always repel each other and unlike poles attract each other.
• Poles always exist in pairs : Single pole can never exist.

Question 12. Explain the attractive property of a magnet with the help of an experiment. Answer: Take iron filling on a piece of paper. Bring a bar magnet near it. Iron filling will cling to it. It shows the attractive property of magnet.

Question 14. How are the magnets kept safely ? What is the role of keepers in storing the magnets ? Answer: When magnets are not in use they should be kept and stored in magnetic keepers. The magnetic keeper are the pieces of soft iron. A magnetic keeper has a card board with one or two iron soft pieces. Two magnets are placed in such a way that their opposite poles are close to each other and then a soft iron keeper is attached with it.

Question 17. State two ways of increasing the strength of an electro Magnet Answer: Strength of the electromagnet: The strength of the electromagnet can be increased:

• by increasing the current in the coil, and
• by increasing the total number of turns of the coil.

Question 19. State three important uses of a magnet. Answer: Use of magnet:

• Magnets are used in magnetic compass, door bells, refrigerators.
• Magnets are used in dynamos, motors, loudspeakers, microphones etc.
• Ceramic magnets are used in computers.
• Magnets are used in toys to give magic effect.

Question 21. In which direction does a suspended bar magnet come to rest? Give reason. Answer: A magnet always rests in North and South direction, i.e. N-end always towards North of Earth and S-end towards South of Earth.

Question 22. State three differences between the temporary and permanent magnets. Answer: Temporary magnet

• It is made up of soft iron.
• The magnet which loses its magnetism as soon as magnetising force is removed away from it.
• Because of its weak power, it is not used to make iron piece into magnet.

Permanent magnets

• It is made up of steel, cobalt and nickel.
• The magnet, which does not lose its magnetic properties easily is called permanent magnet.
• It can convert ordinary piece of iron into a temporary magnet.

Question 23. State three ways of demagnetising a magnet. Answer: A magnet can be demagnetized in the following ways 

• rough handling
• hammering the magnet several times.
• passing an alternating current around the magnet.
• dropping the magnet on the floor several times.
• heating the magnet to a very high temperature.

Question 24. Suggest one way to recognise the magnetic field of the earth. Answer: If we suspend a magnet such that it is free to swing, we see that it always rests in the north-south direction. The north pole of the magnet lies in the geographic north direction and the south pole of the magnet lies in the geographic south direction. So it aligns itself in N-S direction.

Question 25. Name the material of core of an electromagnet for

• temporary magnet
• permanent magnet.
• They are made of soft iron.
• They are made of iron, steel, cobalt, nickel or an alloy called ANILCO.

Question 27. Describe an experiment to illustrate that like poles repel while the unlike poles attract. Answer:

• Take two bar magnets A and B. Suspend one magnet A with a silk thread from a support so that it is free to swing. The magnet will come to rest in the north-south direction. The north pole of the magnet is in the north direction and the south pole of the magnet is in the south direction.

Question 28. What are magnetic keepers ? Name its material. Answer: Magnetic keepers are used to store the magnets. Magnetic keepers are small pieces .of soft iron.

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Check Your Understanding

Answer: d = 1720 m

Answer: a = 8.10 m/s/s

Answers: d = 33.1 m and v f = 25.5 m/s

Answers: a = 11.2 m/s/s and d = 79.8 m

Answer: t = 1.29 s

Answers: a = 243 m/s/s

Answer: a = 0.712 m/s/s

Answer: d = 704 m

Answer: d = 28.6 m

Answer: v i = 7.17 m/s

Answer: v i = 5.03 m/s and hang time = 1.03 s (except for in sports commericals)

Answer: a = 1.62*10 5 m/s/s

Answer: d = 48.0 m

Answer: t = 8.69 s

Answer: a = -1.08*10^6 m/s/s

Answer: d = -57.0 m (57.0 meters deep) 

Answer: v i = 47.6 m/s

Answer: a = 2.86 m/s/s and t = 30. 8 s

Answer: a = 15.8 m/s/s

Answer: v i = 94.4 mi/hr

Solutions to Above Problems

d = (0 m/s)*(32.8 s)+ 0.5*(3.20 m/s 2 )*(32.8 s) 2

Return to Problem 1

110 m = (0 m/s)*(5.21 s)+ 0.5*(a)*(5.21 s) 2

110 m = (13.57 s 2 )*a

a = (110 m)/(13.57 s 2 )

a = 8.10 m/ s 2

Return to Problem 2

d = (0 m/s)*(2.60 s)+ 0.5*(-9.8 m/s 2 )*(2.60 s) 2

d = -33.1 m (- indicates direction)

v f = v i + a*t

v f = 0 + (-9.8 m/s 2 )*(2.60 s)

v f = -25.5 m/s (- indicates direction)

Return to Problem 3

a = (46.1 m/s - 18.5 m/s)/(2.47 s)

a = 11.2 m/s 2

d = v i *t + 0.5*a*t 2

d = (18.5 m/s)*(2.47 s)+ 0.5*(11.2 m/s 2 )*(2.47 s) 2

d = 45.7 m + 34.1 m

(Note: the d can also be calculated using the equation v f 2 = v i 2 + 2*a*d)

Return to Problem 4

-1.40 m = (0 m/s)*(t)+ 0.5*(-1.67 m/s 2 )*(t) 2

-1.40 m = 0+ (-0.835 m/s 2 )*(t) 2

(-1.40 m)/(-0.835 m/s 2 ) = t 2

1.68 s 2 = t 2

Return to Problem 5

a = (444 m/s - 0 m/s)/(1.83 s)

a = 243 m/s 2

d = (0 m/s)*(1.83 s)+ 0.5*(243 m/s 2 )*(1.83 s) 2

d = 0 m + 406 m

Return to Problem 6

(7.10 m/s) 2 = (0 m/s) 2 + 2*(a)*(35.4 m)

50.4 m 2 /s 2 = (0 m/s) 2 + (70.8 m)*a

(50.4 m 2 /s 2 )/(70.8 m) = a

a = 0.712 m/s 2

Return to Problem 7

(65 m/s) 2 = (0 m/s) 2 + 2*(3 m/s 2 )*d

4225 m 2 /s 2 = (0 m/s) 2 + (6 m/s 2 )*d

(4225 m 2 /s 2 )/(6 m/s 2 ) = d

Return to Problem 8

d = (22.4 m/s + 0 m/s)/2 *2.55 s

d = (11.2 m/s)*2.55 s

Return to Problem 9

(0 m/s) 2 = v i 2 + 2*(-9.8 m/s 2 )*(2.62 m)

0 m 2 /s 2 = v i 2 - 51.35 m 2 /s 2

51.35 m 2 /s 2 = v i 2

v i = 7.17 m/s

Return to Problem 10

(0 m/s) 2 = v i 2 + 2*(-9.8 m/s 2 )*(1.29 m)

0 m 2 /s 2 = v i 2 - 25.28 m 2 /s 2

25.28 m 2 /s 2 = v i 2

v i = 5.03 m/s

To find hang time, find the time to the peak and then double it.

0 m/s = 5.03 m/s + (-9.8 m/s 2 )*t up

-5.03 m/s = (-9.8 m/s 2 )*t up

(-5.03 m/s)/(-9.8 m/s 2 ) = t up

t up = 0.513 s

hang time = 1.03 s

Return to Problem 11

(521 m/s) 2 = (0 m/s) 2 + 2*(a)*(0.840 m)

271441 m 2 /s 2 = (0 m/s) 2 + (1.68 m)*a

(271441 m 2 /s 2 )/(1.68 m) = a

a = 1.62*10 5 m /s 2

Return to Problem 12

• (NOTE: the time required to move to the peak of the trajectory is one-half the total hang time - 3.125 s.)

First use:  v f  = v i  + a*t

0 m/s = v i  + (-9.8  m/s 2 )*(3.13 s)

0 m/s = v i  - 30.7 m/s

v i  = 30.7 m/s  (30.674 m/s)

Now use:  v f 2  = v i 2  + 2*a*d

(0 m/s) 2  = (30.7 m/s) 2  + 2*(-9.8  m/s 2 )*(d)

0 m 2 /s 2  = (940 m 2 /s 2 ) + (-19.6  m/s 2 )*d

-940  m 2 /s 2  = (-19.6  m/s 2 )*d

(-940  m 2 /s 2 )/(-19.6  m/s 2 ) = d

Return to Problem 13

-370 m = (0 m/s)*(t)+ 0.5*(-9.8 m/s 2 )*(t) 2

-370 m = 0+ (-4.9 m/s 2 )*(t) 2

(-370 m)/(-4.9 m/s 2 ) = t 2

75.5 s 2 = t 2

Return to Problem 14

(0 m/s) 2 = (367 m/s) 2 + 2*(a)*(0.0621 m)

0 m 2 /s 2 = (134689 m 2 /s 2 ) + (0.1242 m)*a

-134689 m 2 /s 2 = (0.1242 m)*a

(-134689 m 2 /s 2 )/(0.1242 m) = a

a = -1.08*10 6 m /s 2

(The - sign indicates that the bullet slowed down.)

Return to Problem 15

d = (0 m/s)*(3.41 s)+ 0.5*(-9.8 m/s 2 )*(3.41 s) 2

d = 0 m+ 0.5*(-9.8 m/s 2 )*(11.63 s 2 )

d = -57.0 m

(NOTE: the - sign indicates direction)

Return to Problem 16

(0 m/s) 2 = v i 2 + 2*(- 3.90 m/s 2 )*(290 m)

0 m 2 /s 2 = v i 2 - 2262 m 2 /s 2

2262 m 2 /s 2 = v i 2

v i = 47.6 m /s

Return to Problem 17

( 88.3 m/s) 2 = (0 m/s) 2 + 2*(a)*(1365 m)

7797 m 2 /s 2 = (0 m 2 /s 2 ) + (2730 m)*a

7797 m 2 /s 2 = (2730 m)*a

(7797 m 2 /s 2 )/(2730 m) = a

a = 2.86 m/s 2

88.3 m/s = 0 m/s + (2.86 m/s 2 )*t

(88.3 m/s)/(2.86 m/s 2 ) = t

t = 30. 8 s

Return to Problem 18

( 112 m/s) 2 = (0 m/s) 2 + 2*(a)*(398 m)

12544 m 2 /s 2 = 0 m 2 /s 2 + (796 m)*a

12544 m 2 /s 2 = (796 m)*a

(12544 m 2 /s 2 )/(796 m) = a

a = 15.8 m/s 2

Return to Problem 19

v f 2 = v i 2 + 2*a*d

(0 m/s) 2 = v i 2 + 2*(-9.8 m/s 2 )*(91.5 m)

0 m 2 /s 2 = v i 2 - 1793 m 2 /s 2

1793 m 2 /s 2 = v i 2

v i = 42.3 m/s

Now convert from m/s to mi/hr:

v i = 42.3 m/s * (2.23 mi/hr)/(1 m/s)

v i = 94.4 mi/hr

Return to Problem 20

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Physics Magnetism

Displaying all worksheets related to - Physics Magnetism .

Worksheets are Work intro to magnetism, Physics work lesson 20 magnetism, Electricity and magnetism, Magnetic elds and forces, Chapter 22 magnetism, Magnetism, Electricity and magnetism, Physics 132.

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1. Worksheet Intro to Magnetism

2. physics worksheet lesson 20 magnetism, 3. electricity and magnetism, 4. magnetic elds and forces, 5. chapter 22 magnetism, 6. magnetism, 7. electricity and magnetism, 8. physics 132.